6 from 59 Number Picker: How to use this preset
What the selection means
Use this format when your list has 59 numbered items and you need six different entries. Compared with 6 from 49, the selection size stays at six while the pool includes ten more items. The result contains item numbers, so keep your own numbered list beside the screen.
Using the controls
Choose the number of sets and a tumble time, then press Pick Numbers. Each completed set contains six numbers. Selection order shows which ball emerged first; sorted order changes only the display. A new set refills the chamber, so numbers may return across sets.
An activity to try
Prepare 59 revision questions and give each one a number. Pick one set, then answer the six selected questions. If you generate several sets, a question can return in a later set because the chamber starts again with all 59 balls. For a shorter question bank, change the pool size in Custom Preset.
Create your own version with PhysPicks
Choose the number range and how many numbers to pick, then adjust the mixing time to make a number-picking game for your activity.
Customize a number pickerWhat are the probabilities?
These calculations assume uniform selection without replacement within each pool and independent chambers. They describe a mathematical model, not measured or certified probabilities for the PhysPicks physics simulation.
| Event defined before the selection | Theoretical probability |
|---|---|
| One specified main number is the first ball out | 1/59 ≈ 1.69% |
| One specified main number appears anywhere in the completed set | 6/59 ≈ 10.17% |
| Exactly one of your 6 preselected main numbers matches (secondary pool ignored) | 17,218,110/45,057,474 ≈ 38.21% |
| One specified complete combination, ignoring order | 1/45,057,474 |
C(59,6) = 45,057,474
For k picks from n numbers, a specified number is included with probability k/n. There are C(n,k) = n! / (k!(n−k)!) unordered sets. With two independent pools, multiply their combination counts. “One specified number appears” is different from “exactly one of my chosen numbers matches”. A previous result does not make a number due next time.
P(X = 1) = C(6,1) × C(53,5) / C(59,6)